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Fix bug where state cache used lots of memory 

The state cache bases its size on the sum of the size of entries. The
size of the entry is calculated once on insertion, so it is important
that the size of entries does not change.

The DictionaryCache modified the entries size, which caused the state
cache to incorrectly think it was smaller than it actually was.
pull/3005/head
Erik Johnston 2018-03-15 15:40:13 +00:00
parent 2a376579f3
commit 7c7706f42b
2 changed files with 9 additions and 5 deletions
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6
synapse/util/caches/dictionary_cache.py
View File

@ -132,9 +132,13 @@ class DictionaryCache(object):
self._update_or_insert(key, value, known_absent)
def _update_or_insert(self, key, value, known_absent):
entry = self.cache.setdefault(key, DictionaryEntry(False, set(), {}))
# We pop and reinsert as we need to tell the cache the size may have
# changed
entry = self.cache.pop(key, DictionaryEntry(False, set(), {}))
entry.value.update(value)
entry.known_absent.update(known_absent)
self.cache[key] = entry
def _insert(self, key, value, known_absent):
self.cache[key] = DictionaryEntry(True, known_absent, value)

8
synapse/util/caches/lrucache.py
View File

@ -154,14 +154,14 @@ class LruCache(object):
def cache_set(key, value, callbacks=[]):
node = cache.get(key, None)
if node is not None:
if value != node.value:
if node.callbacks and value != node.value:
for cb in node.callbacks:
cb()
node.callbacks.clear()
if size_callback:
cached_cache_len[0] -= size_callback(node.value)
cached_cache_len[0] += size_callback(value)
if size_callback:
cached_cache_len[0] -= size_callback(node.value)
cached_cache_len[0] += size_callback(value)
node.callbacks.update(callbacks)