49 lines
		
	
	
		
			1.6 KiB
		
	
	
	
		
			Python
		
	
	
			
		
		
	
	
			49 lines
		
	
	
		
			1.6 KiB
		
	
	
	
		
			Python
		
	
	
| # -*- coding: utf-8 -*-
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| # Copyright 2014-2016 OpenMarket Ltd
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| # Copyright 2020 The Matrix.org Foundation C.I.C.
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| #
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| # Licensed under the Apache License, Version 2.0 (the "License");
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| # you may not use this file except in compliance with the License.
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| # You may obtain a copy of the License at
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| #
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| #     http://www.apache.org/licenses/LICENSE-2.0
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| #
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| # Unless required by applicable law or agreed to in writing, software
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| # distributed under the License is distributed on an "AS IS" BASIS,
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| # WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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| # See the License for the specific language governing permissions and
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| # limitations under the License.
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| from itertools import islice
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| from typing import Iterable, Iterator, Sequence, Tuple, TypeVar
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| 
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| T = TypeVar("T")
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| 
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| 
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| def batch_iter(iterable: Iterable[T], size: int) -> Iterator[Tuple[T]]:
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|     """batch an iterable up into tuples with a maximum size
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| 
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|     Args:
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|         iterable (iterable): the iterable to slice
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|         size (int): the maximum batch size
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| 
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|     Returns:
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|         an iterator over the chunks
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|     """
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|     # make sure we can deal with iterables like lists too
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|     sourceiter = iter(iterable)
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|     # call islice until it returns an empty tuple
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|     return iter(lambda: tuple(islice(sourceiter, size)), ())
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| 
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| 
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| ISeq = TypeVar("ISeq", bound=Sequence, covariant=True)
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| 
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| 
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| def chunk_seq(iseq: ISeq, maxlen: int) -> Iterable[ISeq]:
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|     """Split the given sequence into chunks of the given size
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| 
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|     The last chunk may be shorter than the given size.
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| 
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|     If the input is empty, no chunks are returned.
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|     """
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|     return (iseq[i : i + maxlen] for i in range(0, len(iseq), maxlen))
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