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Don't show 'unpin' for persistent widgets 

This will mostly fix https://github.com/vector-im/element-web/issues/15139
although it could still break in a race condition.
pull/21833/head
David Baker 2020-09-10 14:30:35 +01:00
parent 017765df24
commit eeb4c5696f
2 changed files with 10 additions and 8 deletions
Show Stats Download Patch File Download Diff File Expand all files Collapse all files

6
src/components/views/context_menus/WidgetContextMenu.js
View File

@ -26,8 +26,8 @@ export default class WidgetContextMenu extends React.Component {
// Callback for when the revoke button is clicked. Required.
onRevokeClicked: PropTypes.func.isRequired,
// Callback for when the unpin button is clicked. Required.
onUnpinClicked: PropTypes.func.isRequired,
// Callback for when the unpin button is clicked. If absent, unpin will be hidden.
onUnpinClicked: PropTypes.func,
// Callback for when the snapshot button is clicked. Button not shown
// without a callback.
@ -86,11 +86,13 @@ export default class WidgetContextMenu extends React.Component {
);
}
if (this.props.onUnpinClicked) {
options.push(
<MenuItem className="mx_WidgetContextMenu_option" onClick={this.onUnpinClicked} key="unpin">
{_t("Unpin")}
</MenuItem>,
);
}
if (this.props.onReloadClicked) {
options.push(

2
src/components/views/elements/AppTile.js
View File

@ -841,7 +841,7 @@ export default class AppTile extends React.Component {
contextMenu = (
<ContextMenu {...aboveLeftOf(elementRect, null)} onFinished={this._closeContextMenu}>
<WidgetContextMenu
onUnpinClicked={this._onUnpinClicked}
onUnpinClicked={ActiveWidgetStore.getWidgetPersistence(this.props.app.id) ? null : this._onUnpinClicked}
onRevokeClicked={this._onRevokeClicked}
onEditClicked={showEditButton ? this._onEditClick : undefined}
onDeleteClicked={showDeleteButton ? this._onDeleteClick : undefined}